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1899 Iowa gubernatorial election

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1899 Iowa gubernatorial election

← 1897 November 7, 1899 1901 →
 
Nominee L. M. Shaw Frederick Edward White
Party Republican Democratic
Popular vote 239,464 183,301
Percentage 55.26% 42.30%

County results
Shaw:      40-50%      50-60%      60-70%      70-80%
White:      40-50%      50-60%

Governor before election

L. M. Shaw
Republican

Elected Governor

L. M. Shaw
Republican

The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote.

General election

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Candidates

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Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • Marshall W. Atwood, Prohibition
  • Charles Lloyd, People's
  • M. J. Kremer, Socialist Labor
  • C. C. Heacock, United Christian

Results

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1899 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican L. M. Shaw (incumbent) 239,464 55.26%
Democratic Frederick Edward White 183,301 42.30%
Prohibition Marshall W. Atwood 7,639 1.76%
Populist Charles Lloyd 1,698 0.39%
Socialist Labor M. J. Kremer 757 0.18%
Independent C. C. Heacock 484 0.11%
Majority 56,163
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 7, 2020.