Indivisible plexes in latin squares

D Bryant, J Egan, B Maenhaut, IM Wanless - Designs, Codes and …, 2009 - Springer
… then there exists a latin square of order n composed of 2m disjoint indivisible k-plexes. Also,
… = 3k, n = 4k or n ≥ 5k, we construct a latin square of order n containing an indivisible k-plex. …

Bachelor latin squares with large indivisible plexes

J Egan - Journal of Combinatorial Designs, 2011 - Wiley Online Library
… Clearly, the existence of indivisible plexes has algorithmic implications when we seek to
divide a latin square into parallel plexes. The existence of indivisible k-plexes for arbitrarily …

Indivisible partitions of latin squares

J Egan, IM Wanless - Journal of statistical planning and inference, 2011 - Elsevier
latin square of order n with a partition into indivisible k-plexes… some latin square of order n
contains an indivisible k-plex. … of indivisible plexes and partitions in latin squares of order at …

A generalisation of transversals for Latin squares

IM Wanless - the electronic journal of combinatorics, 2002 - combinatorics.org
… a k-plex to be a partial latin square of … latin squares and confirm this for orders n ≤ 8.
Finally, we demonstrate the existence of indivisible k-plexes, meaning that they contain no c-plex

Latin squares with no small odd plexes

J Egan, IM Wanless - Journal of Combinatorial Designs, 2008 - Wiley Online Library
… We define the plex range of a Latin square L, to be the set of values of k for which a k-plex is
… This article sheds some light on the existence of indivisible plexes of certain sizes and our …

Transversals in Latin squares: a survey

IM Wanless - Surveys in combinatorics, 2011 - books.google.com
… For a detailed study of the indivisible partitions of latin squares … there is a latin square of order
n containing an indivisible k-plex. … a latin square of order n containing an indivisible k-plex. …

[HTML][HTML] Transversals, indivisible plexes and partitions of latin squares

J Egan - Bulletin of the Australian Mathematical Society, 2011 - journal.austms.org.au
… > 2, there exists a latin square of order n with two parallel indivisible ⌊ n 2 ⌋-plexes. A
… We report on extensive computations of the indivisible partitions of the latin squares of order …

[HTML][HTML] A generalization of plexes of latin squares

K Pula - Discrete mathematics, 2011 - Elsevier
… of Wanless for odd-plexes to show that certain Latin squares have no odd-… of conjectures
of Ryser and Rodney about k -plexes hold for k -weights. In … Indivisible plexes in latin squares

Latin squares with no transversals

NJ Cavenagh, IM Wanless - arXiv preprint arXiv:1609.03001, 2016 - arxiv.org
… 4 there is a latin square of order n that contains a 3-plex but no … a latin square of order 2km
with a k-plex but no k′-plex for … latin square of order n that can be partitioned into indivisible k-…

Among graphs, groups, and latin squares

K Halasz - 2021 - summit.sfu.ca
… whether there exists a latin square with an a-plex and a c-plex but no b-plex for odd integers
a… , 56] studying indivisible plexes, or k-plexes which do not contain an l-plex for any positive …