Day 92 of #100daysofcodechallenge
Todays Topic was Minimum Increment to Make Array Unique.
Problem Description:
Today's challenge involved finding the minimum number of increments required to make all elements in an integer array nums unique.
Explanation:
1) Finding Minimum and Maximum: We identify the smallest element (x0) and the largest element (M) in the nums array.
2) Frequency Array: We create a frequency array freq with a size of M + n to accommodate potential increments beyond the existing elements.
3) Counting Occurrences: We iterate through nums and increment the corresponding frequency counts in freq.
4) Tracking Uniqueness: Two variables, cnt and inc, are used to track the number of non-unique elements (cnt) and the total number of increments (inc) required.
5) Iterating through Potential Values: We iterate through a range encompassing both existing values and potential increments (x0 to n + M).
6) Handling Duplicates:
i) For each value, we check its frequency (f).
ii) If f is less than or equal to 1 (unique), we move on to the next value.
Otherwise, we:
1) Increase the frequency of the next potential value (shifting the duplicate).
2) Decrease the frequency of the current value.
3) Update the inc count by the number of duplicates shifted.
7) Early Exit: Once cnt becomes equal to n - 1 (all but one element unique), we exit the loop as the minimum number of increments has been achieved.
#leetcode #bytexl #paruluniversity sai mahidar
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