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1894 Rhode Island gubernatorial election

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1894 Rhode Island gubernatorial election

← 1893 April 4, 1894 1895 →
 
Nominee Daniel Russell Brown David S. Baker
Party Republican Democratic
Popular vote 29,157 22,650
Percentage 53.15% 41.29%

Governor before election

Daniel Russell Brown
Republican

Elected Governor

Daniel Russell Brown
Republican

The 1894 Rhode Island gubernatorial election was held on April 4, 1894. Incumbent Republican Daniel Russell Brown defeated Democratic nominee David S. Baker with 53.15% of the vote.

General election

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Candidates

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Major party candidates

  • Daniel Russell Brown, Republican
  • David S. Baker, Democratic

Other candidates

  • Henry B. Metcalf, Prohibition
  • Charles G. Baylor, Socialist Labor
  • Henry A. Burlingame, People's

Results

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1894 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Daniel Russell Brown (incumbent) 29,157 53.15%
Democratic David S. Baker 22,650 41.29%
Prohibition Henry B. Metcalf 2,241 4.09%
Socialist Labor Charles G. Baylor 592 1.08%
Populist Henry A. Burlingame 223 0.41%
Majority 6,507
Turnout
Republican hold Swing

References

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  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 19, 2020.